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<H3> Allocating generators of level 0 </H3>
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<P>
<A NAME="IDX449"></A>
<DL>
<DT><U>Function:</U> ap_generator0_t <B>ap_generator0_make</B> <I>(ap_gentyp_t <VAR>gentyp</VAR>, ap_linexpr0_t* <VAR>linexpr</VAR>)</I>
<DD>Create a generator of type <VAR>gentyp</VAR> with the expression
<VAR>linexpr</VAR>.
</P><P>
The expression is not duplicated, just pointed to, so it becomes
managed via the generator.
</DL>
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<A NAME="IDX450"></A>
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<DT><U>Function:</U> ap_generator0_t <B>ap_generator0_copy</B> <I>(gent ap_generator0_t* <VAR>gen</VAR>)</I>
<DD>Duplication
</DL>
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<DL>
<DT><U>Function:</U> void <B>ap_generator0_clear</B> <I>(ap_generator0_t* <VAR>gen</VAR>)</I>
<DD>Clear the generator.
</DL>
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<DT><U>Function:</U> void <B>ap_generator0_fprint</B> <I>(FILE* <VAR>stream</VAR>, gent ap_generator0_t* <VAR>gen</VAR>, char** <VAR>name_of_dim</VAR>);</I>
<DD>Print the linear generator on stream <VAR>stream</VAR>, using the array
<VAR>name_of_dim</VAR> to convert dimensions to variable names. If
<VAR>name_of_dim</VAR> is <CODE>NULL</CODE>, the dimensions are named
<CODE>x0,x1,...</CODE>.
</DL>
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<A NAME="Arrays of generators of level 0"></A>
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